Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-21 05:31Z
∫₀^∞ e^(-n²) dn = √π / 2
e^{i\pi} + 1 = 0
d/dθ [θ^3] = 3θ^2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
89K
\frac{12}{7} \sum_{i=1}^{n} i^{2}
det| 7 9 ; 1 8 | = 47
361K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
176K
F = G m₁m₂ / r²