Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-08-24 13:39Z
det| 11 5 ; 3 12 | = 117
det| 4 1 ; 6 5 | = 14
394K
E = mc²
det| 5 3 ; 7 6 | = 9
112K
det| 9 7 ; 3 10 | = 69
det| 11 4 ; 5 12 | = 112
ΔS ≥ 0
∫₀^∞ e^(-θ²) dθ = √π / 2
2H₂ + O₂ → 2H₂O
∇ × E = −∂B/∂t
det| 4 1 ; 2 5 | = 18
10r² + 8r + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
ΔS ≥ 0