Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-08-30 11:36Z
ω = 2πf
det| 4 1 ; 6 5 | = 14
136K
6ψ² + 6ψ + 5 = 0
det| 5 3 ; 7 6 | = 9
411K
N₂ + 3H₂ ⇌ 2NH₃
PV = nRT
8ψ² + 2ψ + 0 = 0
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
5r² + 2r + 3 = 0
5α² + 6α + 2 = 0
d/dz [z^1] = 1z^0
N₂ + 3H₂ ⇌ 2NH₃
7n² + 6n + 6 = 0
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1