Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-08-26 03:21Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 1 ; 6 5 | = 14
257K
7ψ² + 3ψ + 4 = 0
det| 5 3 ; 7 6 | = 9
365K
ΔS ≥ 0
ΔS ≥ 0
3θ² + 1θ + 6 = 0
det| 5 3 ; 1 6 | = 27
e^{i\pi} + 1 = 0
det| 10 4 ; 1 11 | = 106
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
9n² + 6n + 5 = 0
\frac{9}{6} \sum_{i=1}^{n} i^{2}