Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:17Z
∑_{k=1}^{n} k = n(n+1)/2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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3β² + 6β + 2 = 0
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 9 4 ; 1 10 | = 86
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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