Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 03:36Z
∇ × E = −∂B/∂t
det| 4 8 ; 3 5 | = -4
234K
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
233K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 9 4 ; 1 10 | = 86
375K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-ψ²) dψ = √π / 2
223K
∇²θ = 0
ΔS ≥ 0
4n² + 4n + 3 = 0
6β² + 5β + 0 = 0