Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:41Z
11t² + 7t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
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det| 9 4 ; 1 10 | = 86
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E = mc²
det| 4 6 ; 4 5 | = -4
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
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CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-ψ²) dψ = √π / 2
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