Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:02Z
∑_{k=1}^{n} k = n(n+1)/2
det| 5 6 ; 2 6 | = 18
479K
8β² + 2β + 0 = 0
det| 7 4 ; 4 8 | = 40
276K
∑_{k=1}^{n} k = n(n+1)/2
det| 3 7 ; 2 4 | = -2
191K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
390K
det| 5 9 ; 7 6 | = -33
1K
∫₀^∞ e^(-t²) dt = √π / 2
338K
CH₄ + 2O₂ → CO₂ + 2H₂O
416K