Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 15:41Z
d/dz [z^3] = 3z^2
∑_{k=1}^{n} k = n(n+1)/2
479K
6φ² + 8φ + 0 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
276K
ω = 2πf
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
390K
det| 10 8 ; 7 11 | = 54
det| 5 6 ; 2 6 | = 18
det| 7 6 ; 1 8 | = 50
338K
iħ ∂ψ/∂t = Ĥψ
det| 6 6 ; 3 7 | = 24
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